Question

What is the 12th term in the sequence?

an=−16+2n


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Answer 1

Input 12 for n.

$a_{12}$ = -16 + 2(12)
$a_{12}$ = -16 + 24
$a_{12}$ = 8

The 12th term in the sequence is 8.

Answer 2

This question is based on the sequence.Therefore, the value of $12^{th}$ term  is 8.

Given:

$a_n = -16+2n$

We have to find the $12^{th}$ term in the given sequence.

Now, putting n = 1 in given expression.

We get,

$a_1 = -16 +2(1)\\a_1 = -16+2\\a_1=-14$                  $a_2 = -16 +2(2)\\a_2 = -16+4\\a_1=-12$                   $a_3= -16 +2(3)\\a_3 = -16+6\\a_1=-10$

Now, find the common difference d is,

$d= a_2 - a_1\\d= -12-(-14)\\d= 2$

Therefore, the common difference d is 2.

Now, we have the value $a_1 = -14 \;and \;d= 2$.

We have to find the $12^{th}$ term of given sequence.

$a_n = a + (n-1) \times d\\a_1_2 =-14+(12-1) 2\\a_1_2 =-14+22\\a_1_2 = 8$

Therefore, the value of $12^{th}$ term is 8.

For more details, please refer this link:

https://brainly.com/question/18109692