slope of a line = (y2-y1)/(x2-x1)
In this problem:
y2= 1
y1= 0
x2=4
x1= 3
m = (y2-y1)/(x2-x1)
m = (1-0)/(4-3)= 1/1= 1
y= mx+b (line equation)
y-intercept occurs when x=0. So, plug in a point to find b.
I used (4,1)
y=mx+b
y= (1)x+b
1=(1)(4)+b
1=4+b
b= -3
Y-intercepts of the x-axis at (0,-3). Y-intercept= -3
Any further questions?
