[tex]\bf \qquad \textit{Amount for Exponential Decay}\\\\
A=I(1 - r)^t\qquad
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\to &1300\\
r=rate\to 35\%\to \frac{35}{100}\to &0.35\\
t=\textit{elapsed time}\to &3\\
\end{cases}
\\\\\\
A=1300(1-0.35)^3\implies A=1300(0.65)^3[/tex]