Respuesta :

3x^3+3x^2+2x-2                    |  x+3
                                              --------------------
 -3x^3 -9x^2                              3x^2 - 6x+20
------------------------
/       -6x^2+2x+2
       +6x^2 +18x
      -----------------------
         /         20x+2 
                   -20x -60
                -----------------
                    /       -58

(3x^3+3x^2+2x-2 ) : (x+3)= 3x^2 - 6x+20 and the rest is -58
 

Answer:

Quotient = 3x² - 6x + 20

Remainder = -62

Step-by-step explanation:

In long division, we follow the following steps.

Step 1 : write the dividend under the division symbol, and the divisor to the left on the outside.

Step 2 : Divide the first expression.

Step 3 : write the remainder obtained from the first division and write the third expression it will be the new dividend

Step 4 : again divide the dividend write the remainder and fourth expression as a new dividend.

Step 5 : Repeat these steps until you get the expression which is of less degree than the divisor.

Here, the given expression,

[tex]\frac{3x^3+3x^2+2x-2}{x+3}[/tex]

Using above steps,

We obtained,

[tex]\frac{3x^3+3x^2+2x-2}{x+3}=3x^2-6x+20-\frac{62}{x+3}[/tex]

i.e. Quotient = 3x² - 6x + 20

Remainder = -62

Ver imagen slicergiza
ACCESS MORE
EDU ACCESS