Respuesta :
3x^3+3x^2+2x-2 | x+3
--------------------
-3x^3 -9x^2 3x^2 - 6x+20
------------------------
/ -6x^2+2x+2
+6x^2 +18x
-----------------------
/ 20x+2
-20x -60
-----------------
/ -58
(3x^3+3x^2+2x-2 ) : (x+3)= 3x^2 - 6x+20 and the rest is -58
--------------------
-3x^3 -9x^2 3x^2 - 6x+20
------------------------
/ -6x^2+2x+2
+6x^2 +18x
-----------------------
/ 20x+2
-20x -60
-----------------
/ -58
(3x^3+3x^2+2x-2 ) : (x+3)= 3x^2 - 6x+20 and the rest is -58
Answer:
Quotient = 3x² - 6x + 20
Remainder = -62
Step-by-step explanation:
In long division, we follow the following steps.
Step 1 : write the dividend under the division symbol, and the divisor to the left on the outside.
Step 2 : Divide the first expression.
Step 3 : write the remainder obtained from the first division and write the third expression it will be the new dividend
Step 4 : again divide the dividend write the remainder and fourth expression as a new dividend.
Step 5 : Repeat these steps until you get the expression which is of less degree than the divisor.
Here, the given expression,
[tex]\frac{3x^3+3x^2+2x-2}{x+3}[/tex]
Using above steps,
We obtained,
[tex]\frac{3x^3+3x^2+2x-2}{x+3}=3x^2-6x+20-\frac{62}{x+3}[/tex]
i.e. Quotient = 3x² - 6x + 20
Remainder = -62
