Question

What is the center of the circle represented by this equation? (x – 7)2 + (y + 4)2 = 9?

Answer 1

The general form of a circle at center (h,k) and with radius r is:
(x - h)² + (y - k)² = r²

In your case, you can match your equation to:
(x - 7)² + (y - (-4))² = 3²

So you have a circle centered at (7, -4) with a radius of 3.

Answer 2

Answer:

The center of the given equation of circle is (7, -4)

Step-by-step explanation:

given: The equation of circle as $(x-7)^2+(y+4)^2=9$

We have to find the  center of the circle represented by this equation.

Consider the given equation of circle $(x-7)^2+(y+4)^2=9$

The standard equaton of circle with center (h,k) and radius r  is given by

$(x-h)^2+(y-k)^2=r^2$

Compare with given equation, we have,

h = 7 , k = -4 and r = 3

Thus, The center of the given equation of circle is (7, -4)