Newton's second law and the law of universal gravitation of attraction allows to find the result for the speed of the satellite in Earth orbit is:
v = 2.21 10³ m / s
Newton's second law gives a relationship between force, mass and acceleration of bodies.
F = ma
Where F is the force, m the mass and the acceleration.
The law of universal gravitation says that the force between two bodies is proportional to the mass and inversely proportional to the distance between them.
[tex]F= - G \frac{Mm}{r^2}[/tex]
Where G is the universal gravitational constant, M and m the masses of the bodies and r the distance between them.
We substitute
[tex]- G \frac{M}{r^2} = a[/tex]
as the orbit is circular, the acceleration is cenripetal, see attached.
[tex]a = \frac{v^2}{r}[/tex]
Where v is the speed of the satellite.
Let's substitute.
[tex]* G \frac{M}{r^2} = \frac{v^2}{r} \\v^2 = G \frac{M}{r}[/tex]
The distance from the inside of the planet to the satellite is r = 0.82 10⁸ m, the mass of the planet is tabulated M + 5.98 10241 kg. Let's calculate.
[tex]v^2 = 6.67 \ 10^{-11} \ \frac{5.98 \ 10^{24}}{0.82 \ 10^8} \\v= \sqrt{4.864 \ 10^6}[/tex]
v = 2.21 10³ m / s
In conclusion, using Newton's second law and tlaw of universal gravitation of attraction we can find the result for the speed of the satellite in Earth orbit is:
v = 2.21 10³ m / s
Learn more here: brainly.com/question/2746930
