A spring has an unstretched length of 10 cm. it exerts a restoring force f when stretched to a length of 11 cm. part a for what length of the spring is its restoring force 3f?

Respuesta :

13 cm
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The restoring force in the spring will be [tex]3F[/tex] if it is stretched to a length of [tex]\boxed{13\,{\text{cm}}}[/tex].

Further Explanation:

When a spring is we compressed or stretched, there is a force which develops in the spring restoring force of the spring which tends to bring the spring back to normal length.

The restoring force of the spring is expressed as:

[tex]F= k\cdot\Delta x[/tex]                            ......(1)

Here, [tex]F[/tex] is the force developed in the spring due to stretching,   is the spring constant and [tex]11\,{\text{cm}}[/tex] is the change in length of the spring.

[tex]\begin{aligned}\Deltax&= {x_f} - {x_i}\\&= 0.10 - 0.11\\&= 0.01\,{\text{m}}\\\end{aligned}[/tex]

Substitute the values of [tex]F[/tex] and [tex]\Delta x[/tex] in equation (1).

[tex]\begin{aligned}F &= k\cdot 0.01\hfill\\k&=\frac{F}{{0.01}} \hfill\\\end{aligned}[/tex]

The restoring force of [tex]3F[/tex] is experienced by the spring when the stretched length of the spring should be:

[tex]3F = k.\Delta x[/tex]

Substitute [tex]\dfrac{F}{{0.01}}[/tex] for [tex]k[/tex] in above expression.

[tex]\begin{aligned}3F&=\frac{F}{{0.01}} \cdot\Delta x'\\\Delta x' &= 3 \times 0.01\,{\text{m}}\\&=3\,{\text{cm}}\\\end{aligned}[/tex]

Therefore, the new length of the spring will be:

[tex]\begin{aligned}L&={x_o} + \Delta x' \\&= 10\,{\text{cm}} + 3\,{\text{cm}}\\&= 13\,{\text{cm}}\\\end{aligned}[/tex]

Thus, the restoring force in the spring will be [tex]3F[/tex] if it is stretched to a length of [tex]\boxed{13\,{\text{cm}}}[/tex].

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Answer Details:

Grade: High School

Subject: Physics

Chapter: Work and energy

Keywords:  Spring, unstretched length, compressed, stretched, restoring force, 3F, 11 cm, F=kx, natural length of spring.

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