As a car makes a turn, the force of friction acting upon the turned wheels of the car provides centripetal force required for circular motion. Equation to follow are F = mv²/r "Force of friction" Ff= μsN, Normal N=mg Ff=μsmg. Therfore
mv²/r = μsmg cancel mass "m" The formula to follow will be μs = v²/rg
μs = v²/rg μs = (28.89 m/s²)²/ (65 m)(9.8 m/s²) = 1.31
