Answer:
m∠SPQ=[tex]142\°[/tex]
Step-by-step explanation:
we know that
In a Rhombus the diagonals bisect the angles,
so
m∠SPR=m∠QPR
substitute the values
[tex](4x+11)\°=(5x-4)\°[/tex]
solve for x
[tex]5x-4x=11+4[/tex]
[tex]x=15\°[/tex]
m∠SPQ=m∠SPR+m∠QPR
m∠SPQ=[tex](4x+11)\°+(5x-4)\°[/tex]
m∠SPQ=[tex](9x+7)\°[/tex]
m∠SPQ=[tex](9*15+7)\°=142\°[/tex]
