overwatchpotg
overwatchpotg
27-11-2017
Mathematics
contestada
Please solve for b.
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DivineSolar
DivineSolar
27-11-2017
For this one.
[tex]-\frac{9}{3}+b=-1 \ \textgreater \ \mathrm{Divide\:the\:numbers:}\:\frac{9}{3}=3 \ \textgreater \ -3+b=-1[/tex]
[tex]\mathrm{Add\:}3\mathrm{\:to\:both\:sides} \ \textgreater \ -3+b+3=-1+3 \ \textgreater \ Simplify \ \textgreater \ b=2[/tex]
Hope this helps!
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