Answer is: 0.00142 moles of gas are present.
Ideal gas law: p·V = n·R·T.
p = 0.97 atm.; pressure of the gas.
T = 25.3 + 273.15.
T = 298.45 K; temperature of the gas.
V = 35.83 mL ÷ 1000mL/L.
V = 0.03583 L; volume of the gas.
R = 0.08206 L·atm/mol·K; gas constant.
n = 0.97 atm · 0.03583 L ÷ (0.08206 L·atm/mol·K · 298.45 K).
n = 0.00142 mol; amount of the gas.
