Respuesta :
Data:
1) molar mass: 58.0714 g.
2) mass analysis
C: 18 g
H: 3 g
O: 8 g.
Solution
What is the percent composition of all the components in the liquid?
mass of C + mass of H + mass of O = 18g + 3g + 8g = 29 g
Percent composition:
C: (18g / 29g) * 100 = 62%
H: (3g / 29g) * 100 = 10%
O: (8g / 29g) * 100 = 28%
--------------
Total 100%
What is the empirical formula of the compound?
Convert masses to number of moles by dividing each mass by the atomic mass of the correspondant element:
C: 18 g/ 12.0 g/mol = 1.5 mol
H: 3 g / 1.0 g/mol = 3 mol
O: 8 g / 16 g/mol = 0.5 mol
Divide each number of moles by the smaller, i.e. 0.5 mol
=> C: 1.5 mol / 0.5 mol = 3 mol
=> H: 3 mol / 0.5 mol = 6 mol
=> O: 0.5 mol / o.5 mol = 1 mol
=> Empirical formula: C3 H6 O
What is the molecular formula of the unknown liquid?
First,calculate the molar mass of the empirical formula:
C3 H6 O => 3 * 12 g/mol + 6*1 g/mol + 16 g/mol = 58 g/ mol
Secont, given that the molar mass is the same that the empirical mass, the molecular formula is the same empirical formula.
=> Molecular formula = C3 H6 O.
This compound has been identified as a ketone.
Go online and figure out the name of this compound.
It is easy to find that this compound is propanone or acetone (both names are valid).
Now you can go online and find its characteristics and common uses.
Can you identify the killer from this information? How?
Likely they think you can presume that the killer is the actress, because women use acetone regularlty to remove the nail polish.
1) molar mass: 58.0714 g.
2) mass analysis
C: 18 g
H: 3 g
O: 8 g.
Solution
What is the percent composition of all the components in the liquid?
mass of C + mass of H + mass of O = 18g + 3g + 8g = 29 g
Percent composition:
C: (18g / 29g) * 100 = 62%
H: (3g / 29g) * 100 = 10%
O: (8g / 29g) * 100 = 28%
--------------
Total 100%
What is the empirical formula of the compound?
Convert masses to number of moles by dividing each mass by the atomic mass of the correspondant element:
C: 18 g/ 12.0 g/mol = 1.5 mol
H: 3 g / 1.0 g/mol = 3 mol
O: 8 g / 16 g/mol = 0.5 mol
Divide each number of moles by the smaller, i.e. 0.5 mol
=> C: 1.5 mol / 0.5 mol = 3 mol
=> H: 3 mol / 0.5 mol = 6 mol
=> O: 0.5 mol / o.5 mol = 1 mol
=> Empirical formula: C3 H6 O
What is the molecular formula of the unknown liquid?
First,calculate the molar mass of the empirical formula:
C3 H6 O => 3 * 12 g/mol + 6*1 g/mol + 16 g/mol = 58 g/ mol
Secont, given that the molar mass is the same that the empirical mass, the molecular formula is the same empirical formula.
=> Molecular formula = C3 H6 O.
This compound has been identified as a ketone.
Go online and figure out the name of this compound.
It is easy to find that this compound is propanone or acetone (both names are valid).
Now you can go online and find its characteristics and common uses.
Can you identify the killer from this information? How?
Likely they think you can presume that the killer is the actress, because women use acetone regularlty to remove the nail polish.
