Respuesta :

Answer:

The coordinates of point A are (-10,-4). The coordinates of I are (-3.875,-10.125).

Step-by-step explanation:

It is given that the the line AB is divided into equal parts. Therefor distance between two consecutive points are equal.

The point D is mid point of A and F.

[tex](x,y)=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]

[tex](-8.25,-5.75)=(\frac{x+(-6.5)}{2},\frac{y+(-7.5)}{2})[/tex]

[tex]-8.25=\frac{x-6.5}{2}[/tex]

[tex]-16.50=x-6.5[/tex]

[tex]-10=x[/tex]

[tex]-5.75=\frac{y-7.5}{2}[/tex]

[tex]-11.50=y-7.5[/tex]

[tex]-4=y[/tex]

Therefore the coordinates of A are (-10,-4).

Similarly the pint H is midpoint of F and B.

[tex](-4.75,-9.25)=(\frac{x+(-6.5)}{2},\frac{y+(-7.5)}{2})[/tex]

The values of x and y are,

[tex]x=-3[/tex]

[tex]y=-11[/tex]

Therefore the coordinates of B are (-3,-11).

The point I is mid point of HB. H(-4.75,-9.25) and B(-3,-11).

[tex](x,y)=(\frac{-4.75-3}{2},\frac{-9.25-11}{2})[/tex]

[tex](x,y)=(-3.875,-10.125)[/tex]

Therefore the coordinates of I are (-3.875,-10.125).

Answer: The coordinates of point A are (-10,-4). The coordinates of I are (-3.875,-10.125).

Step-by-step explanation:

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