Question

In a dihybrid cross with genotypes JjQq and JJQq, what is the probability of getting an offspring with genotype JjQq? 

Answer 1

1/2 would be the answer because it's the half of both genes:)brainliest ? 

Answer 2

Answer:

1/4

Explanation:

A dihybrid cross is a cross between two individuals in which two different traits are analyzed.

In the problem, the genes are J/j and Q/q.

Parental generation:  

• JjQq, produces four types of gametes with the same probability: $\frac{1}{4} JQ, \frac{1}{4} Jq, \frac{1}{4} jQ, \frac{1}{4} jq$

• JJQq, produces two types of gametes with the same probability: $\frac{1}{2} JQ, \frac{1}{2} Jq$

To analyze the genotypes of the offspring, a Punnett Square is needed. See the image attached. If you count them, the genotype JjQq appears 2 out of 8 times, so the probability of getting that genotype in the offspring is 2/8 = 1/4.