Question

HELP
In ΔSTU, SU = 18 and TU = 13. Find m∠T to the nearest tenth of a degree.

Answer 1

angle T = arctan(18/13)

= 54.16 = 54.2 degrees

Answer 2

Answer:

Measure of ∠T = 54.2°

Step-by-step explanation:

In the given triangle STU, SU = 18 and TU = 13.

We have to find the measure of angle T.

Since tanT = $\frac{Height}{Base}$

tanT = $\frac{SU}{TU}$

tanT = $\frac{18}{13}$

∠T = $tan^{-1}(1.3846)$

∠T = 54.16 ≈ 54.2°