Question

I have a graphing question

Answer 1

The point slope form of the equation of a straight line is given by

$(y-y_1)=m(x-x_1)$

where $(x_1,\ y_1)$ is a point on the line.

Given

$y-3=\frac{3}{4}(x+2) \\ \\ y-3=\frac{3}{4}(x-(-2))$

Thus the line has a slope of 3/4 and passes through the point (-2, 3), we can obtain another point on the line by substituting an arbitrary value for x.

Consider x = 2, then

$y-3= \frac{3}{4} (2+2)= \frac{3}{4} (4)=3 \\ \\ \Rightarrow y=3+3=6$

Thus another point on the line is (2, 6).

The line can then be graphed by joining the two points.