Question

What was the percent of atmospheric co2 in 1850 if it was 280 ppm? move the decimal place 4 digits to the left to get percent (%)?

Answer 1

We know that the atmospheric co2 in 1850 was 280 parts per million. Thus we have that the percentage is 280/1 million * 10000 . Thus we have that the percent of atmospheric co2 in 1850 was 2.8%

Answer 2

Answer: 0.028

Step-by-step explanation:

ppm is defined as the mass of the solute present in one million $10^6$ parts by mass of the solution.

percent is defined  the the mass of the solute present in hundred parts by mass of the solution.

$ppm=\frac{\text {mass of solute}}{\text {mass of solution}}\times 10^6$

Given: Atmospheric $CO_2$ = 280 ppm

$10^6$ parts contain 280 parts

100 parts will contain =$\frac{280}{10^6}\times 100$ = 0.028

Thus the percent of atmospheric $CO_2$ is 0.028.