Question

The sum of three numbers is 140. The third number is 4 times the first. The first number is 8 less than the second. What are the numbers?

Answer 1

a (first number) + b (second number) +c (third number) = 140
c = 4a
a= b - 8, so b = a +8

Next
a + b + c = 140
a + a +8 + 4a = 140
6a + 8 = 140
6a = 140 -8
6a = 132

a = 132/6 = 22
b = a + 8 = 22 + 8 =30
c = 4a = 4x22 = 88

The answer is:
a = 22, b = 30, c = 88