Question

PLEASE HELP !!!!!!!

Relationship A and Relationship B show the change in the temperature for a pot of water on the stove. Relationship B has a greater rate than Relationship A. This table represents Relationship A.

Time (min) 2 , 3 , 7 , 9
Temperature (°C) 61.3 , 64.9 , 79.3 , 86.5

What table could represent Relationship B?

(A) Time (min) 2 , 3 , 7 , 9
Temperature (°C) 61.0 , 64.4 , 78 , 84.8

(B) Time (min) 2 , 3 , 7 , 9
Temperature (°C) 60.6 , 64.3 , 79.1 , 86.5

(C) Time (min) 2 , 3 , 7 , 9
Temperature (°C) 61.8 , 65.3 , 79.3 , 86.3

(D) Time (min) 2 , 3 , 7 , 9
Temperature (°C) 61.0 , 64.6 , 79.0 , 86.2

Answer 1

Because relationship B has a greater rate, the heat should be increasing more.
Thus the answer is B because in the original, the rate from 2 to 3 was 64.9-61.3=3.6 while in table B, the change is 64.3-60.6=3.7 and 3.7>3.6

Answer 2

Answer:

(B) Time (min) 2 , 3 , 7 , 9

Temperature (°C) 60.6 , 64.3 , 79.1 , 86.5

Step-by-step explanation:

The rate of change is found by using the formula for slope:

$m=\frac{y_2-y_1}{x_2-x_1}$

For option A, this gives us

m =(64.4-61.0)/(3-2) = 3.4/1 = 3.4

This is not more than relationship A.

For option B, we have

(64.3-60.6)/(3-2) = 3.7/1 = 3.7

This is more than relationship A.

For option C, we have

(65.3-61.8)/(3-2) = 3.5/1 = 3.5

This is not more than relationship A.

For option D, we have

(64.6-61.0)/(3-2) = 3.6/1 = 3.6

This is not more than relationship A.