Question

What is the equation in point-slope form of a line that passes through the point (−8, 2) and has a slope of 1/2? Drag a number, symbol, or variable to each box to write a point-slope equation for this line.

Answer 1

y - y1 = m(x - x1)
slope(m) = 1/2
(-8,2)....x1 = -8 and y1 = 2
now we sub
y - 2 = 1/2(x - (-8) =
y - 2 = 1/2(x + 8) <===

Answer 2

Answer:

$(y-2)=\frac{1}{2}(x+8)$

Step-by-step explanation:

We are given,

The straight line has slope $\frac{1}{2}$ and passes through point (-8,2).

The point-slope form is given by $(y-y_{1})=m(x-x_{1})$, where m is the slope.

Substituting the values in the above form, we get,

$(y-y_{1})=m(x-x_{1})$

i.e. $(y-2)=\frac{1}{2}(x+8)$.

Hence, the point-slope form is $(y-2)=\frac{1}{2}(x+8)$.