Question

What is the equation of a line that passes through the point (4, 2) and is perpendicular to the line whose equation is y=x3−1 ?

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i just wanted to see if my answer was correct i put y=-3x+14

Answer 1

In this question, the line is perpendicular to the y=x3−1.
I will assume that the y=x3−1  is y=x/3−1 because x^3 wouldn't have a perpendicular line. In this case, the perpendicular line should have a function of y=-1/(1/3)x + C  
y=-3x+C 

If you put the coordinate of (4, 2) into the function, then it would be: 
y=-3x+C 
2= -3(4)+C
C= 2+12=14

The function would be y=-3x+14

Answer 2

Answer:

y = -3x + 14

Step-by-step explanation:

Just took the quiz. Don't forget the negative!!!