Question

What is the net ionic equation for the reaction of nitric acid with lithium hydroxide?

Answer 1

With ease! Lithium hydroxide + nitric acid → lithium nitrate and water

Explanation:

LiOH(aq)+HNO3(aq)→LiNO3(aq)+H2O(l)

Of course, LiOH(aq), and LiNO_3(aq), are the aquated species, which in solution we would represent as Li+(aq), or NO−(aq)3, where water solvates the ion. The net ionic equation is simply:

OH−(aq)+H+(aq)→H2O(l)

Answer 2

Answer: The net ionic equation is written below.

Explanation:

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of nitric acid and lithium hydroxide is given as:

$HNO_3(aq.)+LiOH(aq.)\rightarrow LiNO_3(aq.)+H_2O(l)$

Ionic form of the above equation follows:

$H^+(aq.)+NO_3^-(aq.)+Li^+(aq.)+OH^-(aq.)\rightarrow Li^+(aq.)+NO_3^-(aq.)+H_2O(l)$

As, lithium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

$H^+(aq.)+OH^-(aq.)\rightarrow H_2O(l)$

Hence, the net ionic equation is written above.