Question

The ksp of copper(ii) carbonate, cuco3, is 1.4 × 10-10. calculate the solubility of this compound in g/l.

Answer 1

To solve for the solubility of this compound:Cu ^ + 2 + CO3 ^ -2 = [x] [x] = x^2 1.4 x 10 ^ -10 = x^2 x = 1.1832 x 10 ^ -5 1.1832 x 10 ^ -5 moles/ L x 123.526 g/mol (molar mass) is equals to 1.5 x 10 ^-3 g/L is the solubility of this compound - CuCO3.