Question

Veronica claims that she can throw a dart at a dartboard from a distance of 2 m and hit the 5 cm wide bullseye if she throws the dart horizontally with a speed of 15 m/s. She starts the throw at the same height las the top of the bulls-eye. Is she able to hit the bullseye?

Answer 1

First, find the amount of time for the dart to hit the board using this equation: t = d/v

t = 2 m/ 15 m/s = 0.133 s

Then, find the height the dart has fallen from its initial point using this equation: h = 0.5gt²

h = 0.5(9.81 m/s²)(0.133 s)² = 0.0872 m or 8.72 cm

Since the diameter of the bull's eye is only 5 cm, and you started at the same level of the top of the bull's eye, that means the maximum allowance would only be 5 cm. Since it exceeded to 8.72 cm, it means that Veronica will not hit the bull's eye.

Answer 2

We conclude that Veronica does not hit the bullseye as the full allowance is 5 cm but the height transcended to 0.0872 m

Does Veronica hit the bullseye?

Question Parameters:

a distance of 2 m and hit the 5 cm wide

he dart horizontally with a speed of 15 m/s.

Generally, the equation for the time for the dart to hit   is mathematically given as

t = d/v

Therefore

t = 2 /15

t = 0.133 s

Hence

h = 0.5gt^2

h = 0.5(9.81 )(0.133 s)^2

h= 0.0872 m

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