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The correct answer is option A
There is only one solution x= 8. The solution x=1 is an extraneous solution.
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Check the picture below for steps
The correct answer is option A
There is only one solution x= 8. The solution x=1 is an extraneous solution.
--------------------------
Check the picture below for steps

There is only one solution: x = 8. The solution x = 1 is an extraneous solution.
We have;
√3x+1 −x + 3 =0
So;
√3x+1 = -(−x + 3)
√3x+1 = x - 3
3x+1 = ( x - 3)^2
3x+1 = x^2 - 6x + 9
Then
x^2 - 9x + 8 = 0
We now have to solve the quadratic equation to obtain;
x=8 or x=1
Now plug back x =1 into the original equation;
√3x+1 −x + 3 =0
√3(1) + 1 - (1) + 3 = 4
Plug back x = 8
√3(8) + 1 - 8 + 3 = 0
Hence, there is only one solution: x = 8. The solution x = 1 is an extraneous solution.
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