Let n be the large sprinkler, and n+16 be the smaller one. Then:
1/n+ 1/n+16=1/6
6/n+ 6/n+16=1
6(n+16)+6n=n²+16n
96+12n=n²+16n
n²+4n-96=0
(n+12)(n-8)=0
n=8 or -12
Using the positive value, we get the large sprinkler soaking the lawn in 8 minutes, and the smaller sprinkler taking 24 minutes
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