Suppose we deposit P dollars. What we can work out is P by considering the interest that is being compounded annually.
[tex]\text{Interest: } 3.6% = 0.036pa[/tex]
After the first year, we would have compounded our deposited amount once: [tex] P + P(0.036) = P(1.036)^{1}[/tex]
Using the amount we have in our bank, we compounded it a second and third time: [tex]P(1.036) \cdot (1.036) = P(1.036)^{2}; \text{Third year: } P(1.036)^{3}[/tex]
Let our third year cash be 35 000 to pay off the car.
[tex]P(1.036)^{3} = 35000[/tex]
[tex]P = \frac{35000}{(1.036)^{3}} = $31476.67[/tex]
Thus, P = $31, 476.67, which is the deposit that you need to make on the day.