Question

find the area of a triangle given that
c=40m
b=20m
a=48°

Answer 1

$Area= \frac{1}{2}\cdot c\cdot b\cdot sin \alpha \\\\------------------\\\\A= \frac{1}{2}\cdot 40\cdot20\cdot sin48^0\approx400\cdot0.7431=297.24\ [m^2]\\\\Ans.\ Area\ is\ about\ 297.24\ [m^2]$