Respuesta :
The highlight of this question is the "2:1 ratio."
On the periodic table, bromine, chlorine, and iodine have 7 valence electrons while sulfur, selenium, and polonium have 6, and so these options are feasible founded on their valence electrons. Though, fluorine does not have 1 valence electron and phosphorus and tellurium do not have 2 valence electrons, so C) and D) are spontaneously out, leaving A) and B).
If we know that the sodium will mix in a 2:1 ratio, we know that the charge of the ions must have a 2:1 ratio too; that's how ionic compounds effort. Sodium (Na) has an ion with a charge of +1 (Na+), so in other words, at all ion it mixes with in a 2:1 ratio must have a charge of -2.
Therefore, sulfur, selenium, and polonium have charges of -2.
On the periodic table, bromine, chlorine, and iodine have 7 valence electrons while sulfur, selenium, and polonium have 6, and so these options are feasible founded on their valence electrons. Though, fluorine does not have 1 valence electron and phosphorus and tellurium do not have 2 valence electrons, so C) and D) are spontaneously out, leaving A) and B).
If we know that the sodium will mix in a 2:1 ratio, we know that the charge of the ions must have a 2:1 ratio too; that's how ionic compounds effort. Sodium (Na) has an ion with a charge of +1 (Na+), so in other words, at all ion it mixes with in a 2:1 ratio must have a charge of -2.
Therefore, sulfur, selenium, and polonium have charges of -2.
Answer:
D) nitrogen, phosphorus, arsenic; 5
Explanation:
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