Respuesta :
Answer:
B) 2,598,960 hands
Step-by-step explanation:
This is a combination problem. So we can use the next formula:
[tex]C(n,k)=nCk=\frac{n!}{k!(n-k)!}[/tex]
Where:
[tex]n=Number\hspace{3}of\hspace{3}elements=52\\k=Number\hspace{3}of\hspace{3}combinations= 5[/tex]
So:
[tex]52C_5=\frac{52!}{5!(47!)}=2598960\hspace{3}hands[/tex]