Respuesta :
1 necklace requires 619 in. of wire
1 bracelet requires 313 in. of wire
The total length of wire = 2813.
Let x = the number of necklaces made.
Let y = the number of bracelets made.
The total amount of wire used is 2813 in., therefore
619x + 313y = 2813
y = (2813 -619x)/313
y = 8.9872 - 1.9976x
Create a table of x versus y.
x: 0 1 2 3 4
y: 9 7 5 3 1
Answer:
(0,9), (1,7), (2,5), (3,3), (4,1)
1 bracelet requires 313 in. of wire
The total length of wire = 2813.
Let x = the number of necklaces made.
Let y = the number of bracelets made.
The total amount of wire used is 2813 in., therefore
619x + 313y = 2813
y = (2813 -619x)/313
y = 8.9872 - 1.9976x
Create a table of x versus y.
x: 0 1 2 3 4
y: 9 7 5 3 1
Answer:
(0,9), (1,7), (2,5), (3,3), (4,1)
Answer:
3 of necklace and bracelet.
Step-by-step explanation:
6 1/9w + 3 1/3w = 28 1/3
9 4/9w = 28 1/3
9 4/9w divided by 9 4/9 = 28 1/3 divided by 9 4/9
W = 3 Sets