Question

A 0.02877 g sample of gas occupies 10.0-ml at 289.0 k and 1.10 atm. upon further analysis, the compound is found to be 38.734% c and 61.266% f. what is the molecular formula of the compound? (order: c, x)

Answer 1

Assuming ideal gas, we calculate the number of moles.

PV = nRT

n = PV / RT

n = (1.10 atm) (10 x 10^-3L) / [(0.08205746 L atm / mol K) (289 K)]

n = 4.64 x 10^-4 mol

 

SO the molar mass is:

molar mass = 0.02877 grams / 4.64 x 10^-4 mol

molar mass = 62.02 g/mol

 

The only possible combination is:

C2F2

 

C = 12 * 2 = 24

F = 19 * 2 = 38

24 + 38 = 62 g/mol

Answer 2

PV = mRT: gas law.

M = $\frac{n}{m}$ : molecular mass

Use: M = $\frac{mRT}{PV}$

Where

m = 0.04343 g

P = 1.10 atm

V = 0.0100 L

R = 0.08205746 (14) L atm K  mole  

T = 293.0 K

M: the molecular mass of the gas.

Then take the mass of this molecule, the molecular mass of the atom (C & Cl), and also the proportion of mass given to search out the amount of moles per mole of gas.

Further explanation

The chemical formula is a component of a formula, that has associate understanding of a substance that determines the kind and a relative range of atoms that area unit in this substance. Or in different languages, a formula are often given that contains data concerning the atoms that form up a selected chemical composition.

Chemical formula is split into 2 specifically chemical formula and formula. The formula announces that the formula mentioned will prove the molecules of the mix atoms. whereas the formula is that the original formula of a composition. The chemical formula are often determined if the relative molecular mass is thought.

Learn more

Gas molecular calculations https://brainly.com/question/6250579

Molecular Mass https://brainly.com/question/7233727

Details

Class: highschool

Subject: Chemistry

Keywords: Mole, Formula, Mass