Question

the length of a rectangle is 5 more than twice the width. the perimeter is 130. what is the area?

Answer 1

L the length     W the width 

The length of a rectangle is 5 more than twice the width
L = 5+ 2W

the perimeter is equal the sum of sides =130

L+L+W+W =130

by subtitution we replace L by L = 5+ 2W

5+ 2W+5+ 2W +W+W = 130

6W= 120

w= 20              L = 5+ 2W= 5+ 40=45