Question

Two fair, six-sided number cubes are rolled. What is the probability that the sum of the values shown is less than 4?

2/3
1/12
1/4
1/3

Answer 1

i believe it is 2/3 not sure but i think so :)

Answer 2

Answer:

$\frac{1}{12}$

Step-by-step explanation:

Let S be the sample space, when two fair six-sided number cubes are rolled.

The sample space is in attached pic.

Let E be the event when sum of the values is less than 4.

$E=\left \{ (1,1), (1,2), (2,1) \right \}$

We know that $P(E)=\frac{n(E)}{n(S)}$ i.e $P(E)=\frac{number\:of\:elements\:in\:E}{number\:of\:elements\:in\:S}$

So, $P(E)=\frac{3}{36}=\frac{1}{12}$