Question

find the rectangular coordinates of the point (-4, pi/3)

Answer 1

Answer:

$\texttt{The rectangular coordinates of the point (-4, pi/3)}=(-2,-2\sqrt{3})$

Step-by-step explanation:

Conversion of parametric form of ( r , θ ) to rectangular coordinate can be done by using the formula ( rcosθ , rsinθ ).

Here we need to convert (-4, pi/3) in to rectangular coordinate form.

Which can be converted to rectangular coordinate form as

         $\left ( -4cos\left ( \frac{\pi}{3} \right),-4sin\left ( \frac{\pi}{3} \right)\right )=\left ( -4\times \left ( \frac{1}{2} \right),-4\times \left ( \frac{\sqrt{3}}{2} \right)\right )=(-2,-2\sqrt{3})$

$\texttt{The rectangular coordinates of the point (-4, pi/3)}=(-2,-2\sqrt{3})$

Answer 2

The rectangular coordinates of the point (-4, pi/3) is:

• (-4, pi/3)= (-2, -2$\sqrt{3}$)

What is a Coordinate?

This refers to the system which is used to find out the position of points in a geometric element.

First of all, we have to convert to parametric form

• ( r , θ ) to rectangular coordinate with the use of the formula ( rcosθ , rsinθ ).

Next, we have to convert (-4, pi/3) in to rectangular coordinate form.

(-4 x (1/2), -4 x ($\sqrt{3}$/2)) = n(-2, -2 $\sqrt{3}$)

After the conversion,

This would bring the rectangular coordinate form to:

• (-4, pi/3)= (-2, -2$\sqrt{3}$)

Read more about rectangular coordinates here:

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