Question

A plumber charges $55 for a service call plus $35 per hour. If the plumber's bill was $160, how many hours was he there?

Answer 1

Well first you have to subtract the 55 bc that the phone call 160-55=105 and den take 105 and divide it by 35 105/35=3 the plumber was there for 3 hours

Answer 2

Answer:

Plumber worked for 3 hours.

Step-by-step explanation:

A plumber charges $55 for a service call plus $35 per hour.

Let he works for x hours.

Then for x hours of work charges = $35x

Since plumber charges $55 as a fixed charge so the total charges will be = 55 + 35x

This total amount charged by the plumber equals to $160

and the equation representing this situation will be

55 + 35x = 160

35x = 160 - 55

35x = 105

x = $\frac{105}{35}$

x = 3 hours

Therefore, he worked for 3 hours.