Force applied to round rod is 217 Newtons.
Force applied to pin A is 297 Newtons.
The pliers are basically a pair of simple levers. And like all levers, the product of length and force will remain a constant.
So for the first part, we have the fulcrum at "A" The force applied is 80 N over a length of 95 mm giving us 80 * 95 = 7600.
So the force applied to round rod will be
X * 35 = 7600
And solving for X, gives us
X * 35 = 7600
X = 217.1428571 N
The answer to part 2 is almost as easy. But you need to rethink how the lever is. Instead of the fulcrum being at pin "A", we'll consider it to be at the round rod. So the lever arm that's getting the 80-N of force is now 35+95 = 130 mm long and the short level arm is still 35 mm. So
130 * 80 = 35 * X
Solving for X
130 * 80 = 35 * X
10400 = 35 * X
297.1428571 = X
So the pin is resisting 297 Newtons of force.
