Question

The Punnett square shows the possible genotype combinations of two parents who are heterozygous for a particular trait.

What is the probability of the parents having a child who is homozygous dominant for this trait?
0%
25%
50%
75%

Answer 1

The probability of the parents having a child who is hzygous dominant for this trait is - 25%

In the given question, there is a particular character that has two alleles Y dominant allele and y recessive allele. Both parents are heterozygous for the trait that is encoded as Yy cross with Yy.

• Cross between:  Yy X Yy

• If both parents carry only one copy of a recessive gene, the likelihood of a child have the recessive trait is one in four.

• Offspring are produced: YY: 2Yy: yy
• Hozygous would be represented for dominant - YY
• there is one YY out of 4 offsprings

        (1/4)*100

        = 25%

Thus, the correct probability would be - 25%

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Answer 2

Based on the laws of probability, the probability of the having a child who is h0m0zygous dominant for the trait indicated in the Punnet square is 25%.

What is the probability of the having a child who is h0m0zygous dominant for the trait indicated in the Punnet square?

Assuming the dominant trait is Y and the recessive trait is y.

From the Punnet square, the offspring genotype are: YY, Yy, Yy and yy.

The child having h0m0zygous dominant trait is YY.

Probability = 1/4 = 25%.

Therefore, the probability of the having a child who is h0m0zygous dominant for the trait indicated in the Punnet square is 1/4 or 25%.

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