Consider an airplane flying at a pressure altitude of 31500 ft and a density altitude of 28000 ft. calculate the outside air temperature. (round the final answer to the nearest whole number.)

Respuesta :

its already roundeed to the nearest number beacuse the place holders make it value

Answer:

1° C

Explanation:

Thinking process:

The expression for the temperature of air in terms of the density is given as follows:

T = [tex]\frac{P }{\rho R }[/tex]

where [tex]\rho[/tex] is the density of air

P is the pressure of the air

R is the characteristic gas constant

pressure of air at 31500 ft  ≈ 23 800 Pa

Thus:

T = [tex]\frac{23.800Pa}{1.225* 287.05}[/tex]

  = 1°

   

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