Ax=24 cos(15)=23.1822Ax=24 cos(15)=23.1822
Ay=â’24 sin(15)=â’6.2117Ay=â’24 sin(15)=â’6.2117
and
Bx=0Bx=0
By=8By=8
To find the distance b you want to find the vector that goes from A to 15 km E (vector C). Calling the differnce in A + B and C D, then we know
[math]D = (A + B) - C. So we have for D:
Dx=(Ax+Bx)â’Cx=â’1.8178Dx=(Ax+Bx)â’Cx=â’1.8178
Dy+(Ay+By)â’Cy=1.7883Dy+(Ay+By)â’Cy=1.7883
D=D2x+D2y‾‾‾‾‾‾‾‾âš=2.2567