Question

He density of ice is 0.92 g/cm3; and the density of seawater is 1.03 g/cm3. a large iceberg floats in arctic waters. what fraction of the volume of the iceberg is exposed?

Answer 1

Only about 11% of the volume of the iceberg is exposed.

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Further explanation

The basic formula of pressure that needs to be recalled is:

Pressure = Force / Cross-sectional Area

or symbolized:

$\large {\boxed {P = F \div A} }$

P = Pressure (Pa)

F = Force (N)

A = Cross-sectional Area (m²)

Let us now tackle the problem !

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Given:

Density of Ice = ρ_ice = 0.92 g/cm³

Densiy of Seawater = ρ_seawater = 1.03 g/cm³

Asked:

Volume of the exposed iceberg = ΔV = ?

Solution:

We will use Archimedes' principle to solve the problem as follows:

$w = F$

$mg = \rho_{seawater} g V'$

$\rho_{ice} \ g V = \rho_{seawater} \ g V'$

$V' = ( \rho_{ice} \div \rho_{seawater} ) V$

$V' = (0.92 \div 1.03) V$

$V' = \frac{92}{103} V$

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$\Delta V = V - V'$

$\Delta V = V - \frac{92}{103} V$

$\Delta V = \frac{11}{103}V$

$\Delta V \approx 11 \% V$

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Learn more

• Minimum Coefficient of Static Friction : https://brainly.com/question/5884009
• The Pressure In A Sealed Plastic Container : https://brainly.com/question/10209135
• Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454

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Answer details

Grade: High School

Subject: Physics

Chapter: Pressure

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Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant , Liquid , Pressure