we know that
The formula to convert K to C is equal to
[tex]\° C =\°K - 273.15\°[/tex] --------> equation [tex]1[/tex]
and
The formula to convert C to K is equal to
[tex]\° K =\°C +273.15\°[/tex] --------> equation [tex]2[/tex]
case a) [tex]100\° K[/tex]
convert to C
substitute in the equation [tex]1[/tex]
[tex]\° C =100\°- 273.15\°=-173.15\°[/tex]
therefore
the answer Part a) is
[tex]\° C =-173.15\°[/tex]
case b) [tex]273\° K[/tex]
convert to C
substitute in the equation [tex]1[/tex]
[tex]\° C =273\°- 273.15\°=-0.15\°[/tex]
therefore
the answer Part b) is
[tex]\° C =-0.15\°[/tex]
case c) [tex]6\° K[/tex]
convert to C
substitute in the equation [tex]1[/tex]
[tex]\° C =6\°- 273.15\°=-267.15\°[/tex]
therefore
the answer Part c) is
[tex]\° C =-267.15\°[/tex]
case d) [tex]143\° C[/tex]
convert to K
substitute in the equation [tex]2[/tex]
[tex]\° K =143\°+ 273.15\°=416.15\°[/tex]
therefore
the answer Part d) is
[tex]\° K =416.15\°[/tex]
case e) [tex]573\° C[/tex]
convert to K
substitute in the equation [tex]2[/tex]
[tex]\° K =573\°+ 273.15\°=846.15\°[/tex]
therefore
the answer Part e) is
[tex]\° K =846.15\°[/tex]
