Answer:
Our answer is 3380kg
Explanation:
The force required to move the truck at constant speed in the given case is.
F=Mg sin∅ =(9100kg)(9.8m/s²)sin15° =2.31×10⁴ N
The net force on the truck after the mass is fell down from the truck is
Fnet =F- mg sin∅
ma= F-mg sin∅
m(1.5m/s²) =( 2.31 × 10⁴N) -m(9.8m/s²)sin 15°
Solve for m.
m((1.5m/s²) +(9.8m/s²)sin 15°) =(2.31 ×10⁴ N))
m = 5720kg
Mass of load is.
Δm =M -m =(9100kg) -(5720kg) =3380kg
