Respuesta :
I believe the answer would be c because i think that you multiply the 2
1. D) 300 J
The work done by a constant force is given by:
[tex]W=Fdcos \theta[/tex]
where F is the force applied, d is the distance, and [tex]\theta[/tex] is the angle between the direction of the force and the direction of motion.
In this problem, F=200 N, d=1.5 m while [tex]\theta=0^{\circ}[/tex], because the force is parallel to the motion of the box, therefore the work done is
[tex]W=(200 N)(1.5 m)(cos 0^{\circ})=300 J[/tex]
2. C) 48,000 J
We can use the same formula used in the previous part of the problem:
[tex]W=Fdcos \theta[/tex]
In this case:
F=480 N
d=100 m
[tex]\theta=0^{\circ}[/tex]
So the work done is
[tex]W=(480 N)(100 m)(cos 0)=48,000 J[/tex]