A 6.50-kg object is hung from the bottom end of a vertical spring fastened to an overhead beam. the object is set into vertical oscillations having a period of 3.20 s. find the force constant of the spring.
Answer:
If the period is 3.20 seconds, the frequency is 2Pi/3.20 = 2.42 radians/sec. The natural frequency is sqrt(k/m) (see the reference).
2.42 = sqrt(k/m) = sqrt(k/7)
5.84 = k/7
