The given for the problem:
100 cm^3 butane
Get first the molecular formula of butane and it is C4H10
To solution for the problem is:
2 C4H10 + 13 O2 = 8 CO2 + 10 H2O
n = V/22.4
n (C4H10) = 0.1/22.4 = 0.0047 mol
n (CO2) = 4 · n (C4H10) = 4 · 0.0047 = 0.018 mol