Respuesta :
Let x = the first numberLet y = the second number x + y = 23 eq1 y = 23- x
xy = Product eq2
Substitute eq1 into eq2. Lets get eq2 in terms of x.
Product = x(23 - x)Product = - x2 + 23x
we must find the vertex has coordinate (h, k). h = -b / 2a where:a = -1b = 23
h= -23 / -2 = 11.5
x = 11.5
Substitute this value of x into eq1 to find y. y = 23 - xy = 23 - 11.5y = 11.5
The two numbers that will give the largest product possible are 11.5 and 11.5.
xy = Product eq2
Substitute eq1 into eq2. Lets get eq2 in terms of x.
Product = x(23 - x)Product = - x2 + 23x
we must find the vertex has coordinate (h, k). h = -b / 2a where:a = -1b = 23
h= -23 / -2 = 11.5
x = 11.5
Substitute this value of x into eq1 to find y. y = 23 - xy = 23 - 11.5y = 11.5
The two numbers that will give the largest product possible are 11.5 and 11.5.
The unknown numbers are 11.5 and 11.5
Let the unknown numbers be x and y
If the sum of the numbers is 23, hence;
x + y = 23
x = 23 - y ............. 1
If the product is at maximum, hence;
xy = maximum ......... 2
Substitute equation 1 into 2
(23 - y )y = maximum
23y - y² = maximum
maximum = -y² + 23y
A(y) = -y² + 23y
Since the product A(y) is at maximum, hence dA(y)/dy = 0 as shown:
dA(y)/dy= -2y + 23 = 0
-2y + 23 = 0
2y = 23
y = 23/2
y = 11.5
Since x + y = 23
x = 23 - y
x = 23 - 11.5
x = 11.5
Hence the unknown numbers are 11.5 and 11.5
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