Question

Justin bought a calculafor and a binder that were both 15% off the original price. The original price of the binder was $6.20. Justin spent a total of $107.27. What was the original price of the calculator?

Answer 1

Let

x-----> the original price of the calculator

y-----> the original price of the binder

we know that

$15\%= \frac{15}{100}=0.15$

$(x+y)(1-0.15)=107.27$

$(x+y)(0.85)=107.27$ -----> equation A

$y=6.20$ -----> equation B

substitute the value of y in the equation A and solve for x

$(x+6.20)(0.85)=107.27$

$(x+6.20)=(107.27/0.85)$

$x=(107.27/0.85)-6.20$

$x=126.20-6.20$

$x=\ 120$

therefore

the answer is

the original price of the calculator is $\ 120$

Answer 2

x-----> the original price of the calculator

y-----> the original price of the binder

we know that

-----> equation A

-----> equation B

substitute the value of y in the equation A and solve for x

therefore

the answer is

the original price of the calculator is