Question

Solid potassium hydroxide koh decomposes into gaseous water and solid potassium oxide . write a balanced chemical equation for this reaction.

Answer 1

The chemical formula is pretty straightforward. 2KOH reacts to produce H2O and K2O. This is the balanced chemical reaction between: Solid potassium hydroxide koh decomposing into gaseous water and solid potassium.

Answer 2

Answer:

2KOH(s) ---> K2O(s) + H2O(g)

Explanation:

potassium hydroxide = KOH

water = H2O

potassium oxide = K2O

since KOH decomposes into H2O and K2O there is an arrow after KOH then after that you balance it. Without doing anything, KOH ----> H2O + K2O on the left side of the arrow there is only one K, one O, and one H atoms while on the other side there are 2 H, 2O, and 2K which means we have to put the two in front of the KOH. so then you will have 2K, 2O, 2H on the left-handed side which will equal the number of atoms there are on the right-handed side.

Also dont forget to put whether it is g, s, or aq.

In the instructions it tells you which one is s , g, or aq.