Question

What is the molarity of the two solutions
0.150 mol of NaOH in 1.80 L of solution

Answer 1

1 mole of MgS = 24.3 + 32.1 = 56.4 g

35.1 g MgS x 1 mol / 56.4 g = 0.622 mol

M = 0.622 mol / 0.835 L = 0.745 mol/L